SQL Server : compare data in same table -


my db sql server 2012 sp1.

here table:

  date            f1          f2        f3 2015-07-1         32           5        78 2015-08-20        18          45        67 2015-09-1         64           9        80 2015-09-30        12          78        45

now count sum , select difference value between last , current month, in example selected data should between august , september, example field f1 take unique value august 18 2 values september 64+12=76, count difference 76-18, value of f1 should 58.

thanks in advance.

select       sum(case when month(date) = month(curdatde()) ,  year(date) = year(curdatde()) f1 else null end)- sum(case when month(date) = (month(curdatde())-1) ,  year(date) = year(curdatde()) f1 else null end) as'f1',      sum(case when month(date) = month(curdatde()) ,  year(date) = year(curdatde()) f2 else null end)- sum(case when month(date) = (month(curdatde())-1) ,  year(date) = year(curdatde()) f2 else null end) as'f2',      sum(case when month(date) = month(curdatde()) ,  year(date) = year(curdatde()) f3 else null end)- sum(case when month(date) = (month(curdatde())-1) ,  year(date) = year(curdatde()) f3 else null end) as'f3' table

this works mysql


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