arrays - Ruby enumerable - find up to n occurrences of matching element -

i have following array:

arr = [1, 3, 2, 5, 2, 4, 2, 2, 4, 4, 2, 2, 4, 2, 1, 5]

i want array containing first 3 odd elements.

i know this:

arr.select(&:odd?).take(3)

but want avoid iterating through whole array, , instead return once i've found third match.

i came following solution, believe want:

my_arr.each_with_object([]) |el, memo|    memo << el if el.odd?; break memo if memo.size == 3  end

but there more simple/idiomatic way of doing this?

arr.lazy.select(&:odd?).take(3).force # => [1, 3, 5]

force used force lazy enumerator evaluate. or, use first it's eager:

arr.lazy.select(&:odd?).first(3) # => [1, 3, 5]

TSQL