regex - IGNORECASE errors in Python's re.Scanner? -


there hidden known functionality in re module

import re  def s_ident(scanner, token): return token def s_operator(scanner, token): return "op%s" % token def s_float(scanner, token): return float(token) def s_int(scanner, token): return int(token)  scanner = re.scanner([     (r"[a-za-z]\w*", s_ident),     (r"\d+\.\d*", s_float),     (r"\d+", s_int),     (r"=|\+|-|\*|/", s_operator),     (r"\s+", none),     ])  print scanner.scan("sum = 3*foo + 312.50 + bar") # (['sum', 'op=', 3, 'op*', 'foo', 'op+', 312.5, 'op+', 'bar'], '')

i want use ignorecase flag here seems not work:

import re  def s_ident(scanner, token): return token def s_operator(scanner, token): return "op%s" % token def s_float(scanner, token): return float(token) def s_int(scanner, token): return int(token)  scanner = re.scanner([     (r"(?i)[a-z]\w*", s_ident),     (r"\d+\.\d*", s_float),     (r"\d+", s_int),     (r"=|\+|-|\*|/", s_operator),     (r"\s+", none),     ])  print scanner.scan("sum = 3*foo + 312.50 + bar") # ([], 'sum = 3*foo + 312.50 + bar')

is issue of scanner or error in code? possible implement non-case-sensitive matching using scanner?

this issue reproduced on python 2.7.9.

expected value: (['sum', 'op=', 3, 'op*', 'foo', 'op+', 312.5, 'op+', 'bar'], '')

actual value: ([], 'sum = 3*foo + 312.50 + bar')

you can pass flags parameter constructor.

scanner = re.scanner([     (r"[a-z]\w*", s_ident),     (r"\d+\.\d*", s_float),     (r"\d+", s_int),     (r"=|\+|-|\*|/", s_operator),     (r"\s+", none),     ], flags=re.ignorecase)

source scanner: https://github.com/python/cpython/blob/master/lib/re.py#l345


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