Cannot log in to the MySQL server (PhpMyAdmin) -


i installed both mysql , phpmyadmin via homebrew. following error when try login root , password:

cannot log in mysql server

i can log in mysql via terminal with:

mysql -u root -p

phpmyadmin config:

/* authentication type */ $cfg['servers'][$i]['auth_type'] = 'cookie'; /* server parameters */ $cfg['servers'][$i]['host'] = '127.0.0.1'; $cfg['servers'][$i]['connect_type'] = 'tcp'; $cfg['servers'][$i]['user'] = 'root'; $cfg['servers'][$i]['password'] = 'pass'; $cfg['servers'][$i]['compress'] = false; $cfg['servers'][$i]['allownopassword'] = false;

i'm running on apache. tried solutions on stackoverflow don't seem work. can me?

you can use both localhost or 127.0.0.1 host declaration.

in case can try use localhost , work.


Comments

Post a Comment

Popular posts from this blog

java - WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/board/] in DispatcherServlet with name 'appServlet' -

this question has answer here: why spring mvc respond 404 , report “no mapping found http request uri […] in dispatcherservlet”? 3 answers i trying making simple bbs i'm encountering following error, warn : org.springframework.web.servlet.pagenotfound - no mapping found http request uri [/board/] in dispatcherservlet name 'appservlet' i have tried solve error many times, have failed. how can solve error? here web.xml, controllerand , servlet-context. my web.xml <?xml version="1.0" encoding="utf-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/xmlschema-instance" xsi:schemalocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <filter> <filter-nam...
Read more

1111. appearing after print sequence - php -

morning, i have code takes string of shoe sizes, explodes , puts in table. code works , info displayed correctly on page after table there few 1's after table. i'm confused this. so table looks (in columns of 3 on webpage) available in following sizes: 3 4 5 6 9 10 111 here's codes, purpose of example $x = 3|4|6|10|9 function get_sizes_pipe($x) { $counter = 0; $splits = explode("|",$x); asort($splits); $x = print "<table class='greentable'>"; $x .= print "<thead><tr><th scope='col' colspan='3' abbr='starter'>available in following sizes:</th></tr></thead><tbody><tr>"; foreach ($splits $split) { $entry = print "<td>".$split."</td>"; if($counter == 2){ $entry .= print "</tr><tr>"; $counter =0; } else { $counter++; ...
Read more

android - How to create dynamically Fragment pager adapter -

i unable create dynamic layout each tabs, able create tabs dynamically constructor(public mypageradapter(fragmentmanager fm , int nooftabs)), coudn't inflate view each tabs creating each fragment should dyanmic. public class mypageradapter extends fragmentpageradapter { private final string[] titles = { "categories", "home", "top paid", "top free", "top grossing", "top new paid", "top new free", "trending" }; int nooftabs; **public mypageradapter(fragmentmanager fm , int nooftabs) { super(fm); this.nooftabs = nooftabs; }** /*public mypageradapter(fragmentmanager fm) { super(fm); }*/ @override public charsequence getpagetitle(int position) { return titles[position]; } @override public int getcount() { ...
Read more