jquery - How to fill three text fields by selecting from first drop down menu using MySql in PHP -


i working on website , in have put user details have user name , address , phone , zip code.

all details stored in mysql.

so, in form , if click on user name drop down menu, 3 other text fields automatically filled respective data.

some thing , if username selected of id 13, address , other fields may have this, [insert address field, name=id13]

something that, not sure how works.

note : want auto-populate other 3 fields knowing first option. other 3 options stored in same database first option

my code far

<!-- start presonal information --> <fieldset class="col-md-6">     <legend>shipper data :</legend>      <!-- name -->     <div class="form-group">         <label class="control-label" >shipper<span class="required-field"></span></label>                                        <select type="text" name="shippername" id="shippername" class="form-control">             <option value="0">select</option>             <?php                 $sql=mysql_query("select * customer");                 while($row=mysql_fetch_array($sql)){                     echo '<option value="'.$row['shippername'].'">'.$row['shippername'].'</option>';                 }             ?>         </select>                </div>                                 <div class="row" >                                 <div class="col-sm-6 form-group">                                     <label  class="control-label">address<span class="required-field"></span></label>                                     <input type="text"  name="shipperaddress" id="shipperaddress"class="form-control"  autocomplete="off" required>                                 </div>                                  <div class="col-sm-3 form-group">                                     <label  class="control-label">phone</label>                                     <input type="text" class="form-control" name="shipperphone" id="shipperphone" autocomplete="off" required>                                 </div>                                  <div class="col-sm-3 form-group">                                     <label class="control-label">pin code</i></label>                                     <input type="text" name="shippercc" id="shippercc"class="form-control"  maxlength="20" placeholder="" autocomplete="off" required>                                 </div>                             </div>

check jfiddle in comment

//jquery

$('#shippername').change(function() {     selectedoption = $('option:selected', this);     $("#shipperaddress").val( selectedoption.data('address') );     $("#shipperphone").val( selectedoption.data('phone') );     $("#shippercc").val( selectedoption.data('zipcode') ); });

//php

<select name="shippername" id="shippername">     <option value="0">select</option>     <?php          $sql=mysql_query("select * customer");         while($row=mysql_fetch_array($sql)) {     ?>             <option value="<?php echo $row['shippername'];?>" data-address="<?php echo $row['shipperaddress'] ?>" data-phone="<?php echo $row['shipperphone'] ?>" data-zipcode="<?php echo $row['shippercc'] ?>"><?php echo $row['shippername'];?></option>     <?php            }     ?> </select> <div class="row" >     <div class="col-sm-6 form-group">         <label  class="control-label">address<span class="required-field"></span></label>         <input type="text"  name="shipperaddress" id="shipperaddress"class="form-control"  autocomplete="off" required>     </div>     <div class="col-sm-3 form-group">         <label  class="control-label">phone</label>         <input type="text" class="form-control" name="shipperphone" id="shipperphone" autocomplete="off" required>     </div>     <div class="col-sm-3 form-group">         <label class="control-label">pin code</i></label>         <input type="text" name="shippercc" id="shippercc"class="form-control"  maxlength="20" placeholder="" autocomplete="off" required>     </div> </div>

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