Android, How to retrieve redirect URL from a WebView? -


first surfed web no answer found matching case. want grab specific redirect url webview , keep webview opening it. case instagram redirect url after user authorized app. how it? here code:

    webview = (webview) findviewbyid(r.id.webview1);     webview.getsettings().setjavascriptenabled(true);     webview.getsettings().setloadwithoverviewmode(true);     webview.getsettings().setusewideviewport(true);     webview.getsettings().setbuiltinzoomcontrols(true);     webview.setwebviewclient(new webviewclient());     webview.loadurl("https://api.instagram.com/oauth/authorize/?client_id=my_client_id&redirect_uri=my_redirect_uri&response_type=code");

you have set custom webviewclient overriding shouldoverrideurlloading method webview before loading url.

mwebview.setwebviewclient(new webviewclient()     {         @suppresswarnings("deprecation")         @override         public boolean shouldoverrideurlloading(webview webview, string url)         {             return shouldoverrideurlloading(url);         }          @targetapi(build.version_codes.n)         @override         public boolean shouldoverrideurlloading(webview webview, webresourcerequest request)         {             uri uri = request.geturl();             return shouldoverrideurlloading(uri.tostring());         }          private boolean shouldoverrideurlloading(final string url)         {             log.i(tag, "shouldoverrideurlloading() url : " + url);              // here put code              return true; // returning true means application wants leave current webview , handle url itself, otherwise return false.         }     });  mwebview.loadurl("your url");

checkout example code handling redirect urls , open pdf without download, in webview. https://gist.github.com/ashishdas09/014a408f9f37504eb2608d98abf49500


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