Displaying daily totals between now and x days ago using MYSQL/PHP -


i have table called 'orders' , contains; id, order_total , time fields. 'time' integer , stores unix timestamp...

orders

 | id | order_total  | time          | ------------------------------------- | 1  | 42.00        | 1443355834    | | 2  | 13.00        | 1443460326    | | 3  | 51.00        | 1443468094    | | 4  | 16.00        | 1443477442    | | 5  | 10.00        | 1443606966    | | 6  | 53.00        | 1443608256    |

i want able display in table using php sum, of 'order_total' each day previous 'x' amount of days (or weeks or months) this:

 | date      | order total | --------------------------- | 27/09/15  | 42.00       | | 28/09/15  | 80.00       | | 30/09/15  | 63.00       |

i have made mysql query , php loop kind of works being new mysql over-complicating things , there must easier way ? when kind of works, correctly sum , show order_totals until current day reason combine current day previous day.

here have:

$x = $interval; $y = $x - 1;  while ($x > 0) {     $sql10 = "         select id,                time,                sum(order_total) sum,                date_format(date_sub(from_unixtime($now_time), interval $x day), '%y-%m-%d') thedate            $orderstable          from_unixtime(time) between date_format(date_sub(from_unixtime($now_time), interval $x day),'%y-%m-%d')            , date_format(date_sub(from_unixtime($now_time), interval $y day),'%y-%m-%d')";      $result10 = mysql_query ( $sql10, $cid ) or die ( "couldn't execute query." );      while ( $row = mysql_fetch_array ( $result10) ) {         $order_total = $row ["order_total"];         $thedate = $row ["thedate"];         $sum = $row ["sum"];         $sum = number_format($sum,2);         $thedate = strtotime($thedate);         $thedate = date("d/m/y",$thedate);          print "<tr><td width=\"120\">$thedate</td><td>\$$sum</td></tr>";     }      $x--;     $y--; }

(the string $now_time contains current time unix timestamp hence converting system time can not changed , contains correct local time user)

is there better way ?

you can convert timestamps yyyy mm dd using from_unixtime function , select ones older enough datediff function. today's date provided curdate function.

first of all, query retrieves totals orders older interval , reformats date fields:

$q1 = "select " . $orderstable . ".order_total total, from_unixtime(" . $orderstable . ".time, '%y-%m-%d') short_date " . $orderstable . " datediff(curdate(), short_date) > " . $intervalindays;

then, 1 sums totals of day:

$q2 = "select short_date day, sum(total) total (" . $q1 . ") group short_date";

and perform query stored in $q2 , other operations need display result.
result query should in form:

|    day    |    total    | =========================== | 25/09/15  |  34.00      | | 16/09/15  | 100.00      | | 31/07/14  |   3.20      | |    ...    |     ...     |

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