bash - Find words that are 6 characters in length -


i have file.txt

fhadja ksjfskdasd adasda sada s adasaaa

i need extract words 6 character length there.

example of need obtain result:

fhadja adasda

thank you.

you can use:

grep -e '^.{6}$' file fhadja adasda

or using awk:

awk 'length($0)==6' file fhadja adasda

or using sed:

sed -rn '/^.{6}$/p' file fhadja adasda

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