arrays - Reduce a string to a dictionary in Swift -

what woudl simple way reduce string aaa:111;bbb:222;333;444;ccc:555 dictionary in swift. have following code:

var str = "aaa:111;bbb:222;333;444;ccc:555" var astr = str.componentsseparatedbystring(";").map { (element) -> [string:string] in     var elements = element.componentsseparatedbystring(":")     if elements.count < 2 {         elements.insert("n/a", atindex: 0)     }     return [elements[0]:elements[1]] } 

code above produces array of dictionaries:
[["a": "111"], ["bbb": "222"], ["ukw": "333"], ["ukw": "444"], ["ccc": "555"]]

i want produce
["a": "111", "bbb": "222", "ukw": "333", "ukw": "444", "ccc": "555"]

no mater try, since call map function on array seems impossible convert nature of map function's result.

note: dictionary in string format described either having key:value; format or value; format, in case mapping function add "n/a" being key of unnamed value.

any on matter appreciated.

your map produces array of dictionaries. when want combine them 1, that's perfect job reduce:

func + <k,v>(lhs: dictionary<k,v>, rhs: dictionary<k,v>) -> dictionary<k,v> {     var result = dictionary<k,v>()      (key, value) in lhs {         result[key] = value     }     (key, value) in rhs {         result[key] = value     }      return result }  var str = "aaa:111;bbb:222;333;444;ccc:555" var astr = str     .componentsseparatedbystring(";")     .reduce([string: string]()) {         aggregate, element in         var elements = element.componentsseparatedbystring(":")         if elements.count < 2 {             elements.insert("n/a", atindex: 0)         }         return aggregate + [elements[0]:elements[1]]     }  print(astr) 

swift has no default operator "combine" 2 dictionaries have define one. note + here not commutative: dicta + dictb != dictb + dicta. if key exist in both dictionaries, value second dictionary used.